a better query to delete from hashtags
old query: Delete on hashtags (cost=5089.81..5521.63 rows=6160 width=18) -> Hash Semi Join (cost=5089.81..5521.63 rows=6160 width=18) Hash Cond: (hashtags.id = ht.id) -> Seq Scan on hashtags (cost=0.00..317.28 rows=17528 width=14) -> Hash (cost=5012.81..5012.81 rows=6160 width=20) -> Merge Anti Join (cost=0.70..5012.81 rows=6160 width=20) Merge Cond: (ht.id = hto.hashtag_id) -> Index Scan using hashtags_pkey on hashtags ht (cost=0.29..610.53 rows=17528 width=14) -> Index Scan using hashtags_objects_pkey on hashtags_objects hto (cost=0.42..3506.48 rows=68158 width=14) new query: Delete on hashtags ht (cost=0.70..5012.81 rows=6160 width=12) -> Merge Anti Join (cost=0.70..5012.81 rows=6160 width=12) Merge Cond: (ht.id = hto.hashtag_id) -> Index Scan using hashtags_pkey on hashtags ht (cost=0.29..610.53 rows=17528 width=14) -> Index Scan using hashtags_objects_pkey on hashtags_objects hto (cost=0.42..3506.48 rows=68158 width=14)
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@ -97,12 +97,10 @@ def run(["prune_objects" | args]) do
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|> Repo.delete_all(timeout: :infinity)
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|> Repo.delete_all(timeout: :infinity)
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prune_hashtags_query = """
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prune_hashtags_query = """
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delete from hashtags
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delete from hashtags as ht
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where id in (
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where not exists (
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select id from hashtags as ht
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select 1 from hashtags_objects hto
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left join hashtags_objects as hto
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where ht.id = hto.hashtag_id)
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on hto.hashtag_id = ht.id
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where hto.hashtag_id is null)
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"""
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"""
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Repo.query(prune_hashtags_query)
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Repo.query(prune_hashtags_query)
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